Termination w.r.t. Q of the following Term Rewriting System could not be shown:
Q restricted rewrite system:
The TRS R consists of the following rules:
a1(a1(f2(b, a1(x)))) -> f2(a1(a1(a1(x))), b)
a1(a1(x)) -> f2(b, a1(f2(a1(x), b)))
f2(a1(x), b) -> f2(b, a1(x))
Q is empty.
↳ QTRS
↳ DependencyPairsProof
Q restricted rewrite system:
The TRS R consists of the following rules:
a1(a1(f2(b, a1(x)))) -> f2(a1(a1(a1(x))), b)
a1(a1(x)) -> f2(b, a1(f2(a1(x), b)))
f2(a1(x), b) -> f2(b, a1(x))
Q is empty.
Using Dependency Pairs [1,13] we result in the following initial DP problem:
Q DP problem:
The TRS P consists of the following rules:
A1(a1(f2(b, a1(x)))) -> A1(a1(x))
A1(a1(x)) -> F2(a1(x), b)
A1(a1(x)) -> A1(f2(a1(x), b))
A1(a1(x)) -> F2(b, a1(f2(a1(x), b)))
A1(a1(f2(b, a1(x)))) -> A1(a1(a1(x)))
A1(a1(f2(b, a1(x)))) -> F2(a1(a1(a1(x))), b)
F2(a1(x), b) -> F2(b, a1(x))
The TRS R consists of the following rules:
a1(a1(f2(b, a1(x)))) -> f2(a1(a1(a1(x))), b)
a1(a1(x)) -> f2(b, a1(f2(a1(x), b)))
f2(a1(x), b) -> f2(b, a1(x))
Q is empty.
We have to consider all minimal (P,Q,R)-chains.
↳ QTRS
↳ DependencyPairsProof
↳ QDP
↳ DependencyGraphProof
Q DP problem:
The TRS P consists of the following rules:
A1(a1(f2(b, a1(x)))) -> A1(a1(x))
A1(a1(x)) -> F2(a1(x), b)
A1(a1(x)) -> A1(f2(a1(x), b))
A1(a1(x)) -> F2(b, a1(f2(a1(x), b)))
A1(a1(f2(b, a1(x)))) -> A1(a1(a1(x)))
A1(a1(f2(b, a1(x)))) -> F2(a1(a1(a1(x))), b)
F2(a1(x), b) -> F2(b, a1(x))
The TRS R consists of the following rules:
a1(a1(f2(b, a1(x)))) -> f2(a1(a1(a1(x))), b)
a1(a1(x)) -> f2(b, a1(f2(a1(x), b)))
f2(a1(x), b) -> f2(b, a1(x))
Q is empty.
We have to consider all minimal (P,Q,R)-chains.
The approximation of the Dependency Graph [13,14,18] contains 1 SCC with 5 less nodes.
↳ QTRS
↳ DependencyPairsProof
↳ QDP
↳ DependencyGraphProof
↳ QDP
Q DP problem:
The TRS P consists of the following rules:
A1(a1(f2(b, a1(x)))) -> A1(a1(x))
A1(a1(f2(b, a1(x)))) -> A1(a1(a1(x)))
The TRS R consists of the following rules:
a1(a1(f2(b, a1(x)))) -> f2(a1(a1(a1(x))), b)
a1(a1(x)) -> f2(b, a1(f2(a1(x), b)))
f2(a1(x), b) -> f2(b, a1(x))
Q is empty.
We have to consider all minimal (P,Q,R)-chains.